Competitive exams questions & solutions

  1. The weight of watermelon with 75% is 50 kg. what would be the weight of the same watermelon with 90% water.

The weight of the watermelon with 90% water would be 125 kg.

Tip – Find the constant solid mass. A watermelon consists of water and solid matter. The amount of solid matter stays exactly the same when the water content changes.

Initial total weight:

Initial water percentage= 90%

Solid percentage= 100%-90% = 10%

New water percentage= 75%

Solid percentage= 100%- 75%=25%

New Total weight = 50 kg

Weight of solid mass = 50 x 0.25 = 12.5 kg

So the initial solid mass weight would also be 12,5 kg.

So the initial weight of watermelon would be =

.10 x 12.5 = 125kg.

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2. A shopkeeper marks the price 20% higher and then increases it by another 5%. Find the total profit percentage.

1. Assume Cost Price as ₹.100.

Let the original cost price be ₹.100.

First Increase

The shopkeeper marks the price 20% higher.

First marked price =100+(20% of 100)

=100+20=120

Second Increase

The shopkeeper increases this new price by another 5%.

Final selling price =120+(5% of 120)

=120+6=126

Total Profit = SP – CP

126 – 100 = ₹. 26

The profit percentage is calculated based on the original cost price.

Profit percentage= Profit / CP x 100

26/100 x 100= 26%

Successive increase shortcut method =

Profit % = ( x+y + xy /100)
20+ 5 + 20×5 / 100
20+ 5 + 1 = 26 %

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₹. 8000  compounded half yearly at annual rate of 10% for 1 year. Find the final amount.

Solution :

Principal = ₹. 8000

Rate is equal to 10% per annum

Compounded half yearly = 10% / 2 = 5%

The number of periods in one year is equal to 2.

Formula for half yearly compounded amount

Tip – For half yearly r is taken as r/2 and n is considered as 2 halves = 2

A = P (1 + r/2/100) ^n
A =  8000 x (1 + 0.05)^2 = 8000 x 1.1025 =₹. 8820

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